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Algebra II

Imaginary and Complex Numbers

Lesson

The imaginary unit ii is defined by:

i=1,i2=1i = \sqrt{-1}, \quad i^2 = -1

With ii, we can take the square root of any negative number: 9=91=3i\sqrt{-9} = \sqrt{9} \cdot \sqrt{-1} = 3i.

Complex numbers

A complex number has a real part and an imaginary part: a+bia + bi.

Operations with complex numbers

  • Add/subtract: combine real parts and imaginary parts separately, like adding terms.
  • Multiply: use FOIL like normal binomials. Whenever you see i2i^2, replace it with 1-1.
  • Powers of i cycle: i1=i,  i2=1,  i3=i,  i4=1i^1 = i, \; i^2 = -1, \; i^3 = -i, \; i^4 = 1, then it repeats.

Worked example 1 — adding

(3+2i)+(54i)=82i(3 + 2i) + (5 - 4i) = 8 - 2i

Worked example 2 — multiplying

(2+3i)(1i)(2 + 3i)(1 - i)

FOIL:

=22i+3i3i2= 2 - 2i + 3i - 3i^2

Replace i2i^2 with 1-1:

=2+i+3=5+i= 2 + i + 3 = 5 + i

How to type your answer

Write in the form a+bia + bi or abia - bi. Real part first, then imaginary. No spaces. If the answer is purely real or purely imaginary, write just that part. Examples: 5+i, 8-2i, 3i, -1, -2-5i.

Practice

Work through these. Stuck? Click Get a hint.

Warm-Up

Quick problems to get going.

Problem 1

i2i^2

Problem 2

i4i^4

Problem 3

(2+i)+(3+2i)(2 + i) + (3 + 2i)

Problem 4

(4+3i)(1+2i)(4 + 3i) - (1 + 2i)

Practice

Standard problems matching the lesson.

Problem 5

(3+2i)+(54i)(3 + 2i) + (5 - 4i)

Problem 6

(73i)(2+4i)(7 - 3i) - (2 + 4i)

Problem 7

(6+5i)+(23i)(6 + 5i) + (-2 - 3i)

Problem 8

(14i)(37i)(1 - 4i) - (3 - 7i)

Problem 9

i3i^3

Problem 10

i10i^{10}

Problem 11

(2+3i)(1i)(2 + 3i)(1 - i)

Problem 12

(1+2i)(3+i)(1 + 2i)(3 + i)

Problem 13

(4i)(2+i)(4 - i)(2 + i)

Problem 14

(3+i)(3i)(3 + i)(3 - i)

Problem 15

(1+i)2(1 + i)^2

Problem 16

(2i)2(2 - i)^2

Challenge

Harder problems — edge cases, trickier numbers, multiple steps.

Problem 17

i17i^{17}

Problem 18

(5+2i)(52i)(5 + 2i)(5 - 2i)

Problem 19

(3+4i)+(34i)(3 + 4i) + (3 - 4i)

Problem 20

25\sqrt{-25}

Problem 21

(2+5i)(32i)(2 + 5i)(3 - 2i)

Problem 22

(1+i)3(1 + i)^3