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Algebra I

Absolute Value Equations and Inequalities

Lesson

Absolute value measures distance from zero. So ∣x∣=5|x| = 5 asks: what numbers sit exactly 5 units from zero? There are two answers: x=5x = 5 or x=−5x = -5.

The rule

∣A∣=k  ⟹  A=k  or  A=−k|A| = k \implies A = k \ \text{ or }\ A = -k

Whatever’s inside the bars can equal +k+k or −k-k. Solve both.

Worked example 1

∣x−3∣=5|x - 3| = 5

Split into two equations:

x−3=5orx−3=−5x - 3 = 5 \quad \text{or} \quad x - 3 = -5

Solve each: x=8x = 8 or x=−2x = -2.

Worked example 2 — isolate the absolute value first

2∣x∣+1=112|x| + 1 = 11

Subtract 1, then divide by 2:

∣x∣=5  ⟹  x=5  or  x=−5|x| = 5 \implies x = 5 \ \text{ or }\ x = -5

Absolute value inequalities use the same idea, but the answer is a range.

Two patterns

  • “Less than”: ∣A∣<k|A| < k means −k<A<k-k < A < k— the inside is between the two boundary values (a sandwich).
  • “Greater than”: ∣A∣>k|A| > k means A<−kA < -k or A>kA > k— the inside is outside the two boundaries (two separate pieces).

No solution alert

If the absolute value equals a negative number (after isolating), there is no solution. Absolute value is never negative.

How to type your answer

Enter both solutions separated by a comma: 8,-2. Order doesn’t matter. If there’s only one solution, type just that number.

Practice

Work through these. Stuck? Click Get a hint.

Warm-Up

Quick problems to get going.

Problem 1

∣x∣=4|x| = 4

Problem 2

∣x∣=9|x| = 9

Problem 3

∣x∣=0|x| = 0

Problem 4

∣x∣+1=6|x| + 1 = 6

Practice

Standard problems matching the lesson.

Problem 5

∣x∣=12|x| = 12

Problem 6

∣x−3∣=5|x - 3| = 5

Problem 7

∣x+4∣=6|x + 4| = 6

Problem 8

∣x−2∣=7|x - 2| = 7

Problem 9

∣x+1∣=3|x + 1| = 3

Problem 10

2∣x∣=102|x| = 10

Problem 11

3∣x∣=123|x| = 12

Problem 12

∣x∣−4=1|x| - 4 = 1

Problem 13

∣x∣+2=9|x| + 2 = 9

Problem 14

∣2x∣=8|2x| = 8

Problem 15

∣3x∣=9|3x| = 9

Problem 16

∣x−5∣=0|x - 5| = 0

Problem 17

Thermostat: |T - 70| = 3. Two boundary temperatures?

Problem 18

Measurement error |e| = 0.5. Two possible values?

Challenge

Harder problems — edge cases, trickier numbers, multiple steps.

Problem 19

∣x−1∣=8|x - 1| = 8

Problem 20

∣2x−3∣=5|2x - 3| = 5

Problem 21

∣x+6∣−2=7|x + 6| - 2 = 7

Problem 22

2∣x−1∣=62|x - 1| = 6

Problem 23

∣2x+4∣=10|2x + 4| = 10

Problem 24

Solve |x| < 6 — give the two boundary values.

Problem 25

Solve |x - 4| > 2 — give the two boundary values.

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